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-80((x^2)-57.6x+320)=0
We multiply parentheses
-80x^2+4560x-25600=0
a = -80; b = 4560; c = -25600;
Δ = b2-4ac
Δ = 45602-4·(-80)·(-25600)
Δ = 12601600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12601600}=\sqrt{6400*1969}=\sqrt{6400}*\sqrt{1969}=80\sqrt{1969}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4560)-80\sqrt{1969}}{2*-80}=\frac{-4560-80\sqrt{1969}}{-160} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4560)+80\sqrt{1969}}{2*-80}=\frac{-4560+80\sqrt{1969}}{-160} $
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